Which cobs or strips with LPF-60D-24 driver?

[FREESCRAVEN]

Hi everyone!

I'm starting a new microgrow project in a space : 50 x 45 x 60H cm
Lately I have always used 60w quantum boards, but some chips have burned out and I have neither the knowledge nor the time to repair them, so I would like to replace them with cobs or strips using the driver I have
The Meanwell LPF-60D-24.
Which cobs or strips configuration do you suggest with this driver?
The goal is to have a lamp that doesn't get very hot.
Thank you all!

[PeteR_1]

... I'm starting a new microgrow project in a space : 50 x 45 x 60H cm
Lately I have always used 60w quantum boards, but some chips have burned out and I have neither the knowledge nor the time to repair them, so I would like to replace them with cobs or strips using the driver I have
The Meanwell LPF-60D-24.
Which cobs or strips configuration do you suggest with this driver? The goal is to have a lamp that doesn't get very hot.
Thank you all!

Ten (10) Bridgelux 280 mm EB Gen2 LED Strips can provide adequate PPFD coverage of your 0.225 sq m area with your 60 Watt LED Driver (10 Strips, 3500K, 10500Lm, 157 PPF) will be running relatively "Soft", requiring minimal heatsinking and some stiffening support, an Aluminum Sheet or Baking Pan?.
Good Luck and you're welcome.

For Comparison an HLG 65 V2 LED Light... https://horticulturelightinggroup.com/c ... cts/hlg-65
28 x 24 cm, 4000K, 10800Lm, 156 PPF (umol/s)

Some Calculations:
0.50 m * 0.45 m = 0.225 m2

a... 0.225 * 800 (PPFD Flower CO2 enriched) = 180 PPF req'd (min)
180 PPF / 2.5 PPE (PPE/W) = 72 Watts

b... 0.225 * 600 (PPFD Flower) = 135 PPF req'd (min)
135 PPF / 2.5 PPE (PPE/W) = 54 Watts


Selected Driver:
LPF-60D-24, 14.4 - 24V CC Region, 2.5A @ 24V, 60W, Dim 10 - 100%
MeanWell LPF-60D-24 Datasheets... https://www.meanwell.com/Upload/PDF/LPF ... D-SPEC.PDF

Strip selections:
Bridgelux Gen2 BXEB-L0280Z-3500K, 280 x 24mm, 80CRI, 1195Lm, 17.9 PPF, 175Lm/W, 2.625 PPE, 350mA, 19.5V, 6.825W
180 PPF / 17.9 PPF/Strip = 10 Strips (11950Lm, 179 PPF, 68.25 Watts)
2.625 * 60 Watts (Driver Output) = 157 PPF
60 / 0.89 (Driver Eff) = 67.4 Watts Input (at wall)
10 - Bridgelux Gen2 BXEB-L0280Z-3500K ($28.00 US)... https://www.digikey.com/en/products/det ... pxEgC6AvkA

Other Bridgelux 280mm and 340mm LED Strips... https://www.digikey.com/en/products/fil ... nmtIOpqakA


Notes:
1. Grow Lights should be "Sized" by Grow Area and Plant Specific Growth Stage... download/file.php?id=4438

2. Older "Watts per sq ft sizing" was based on ~ 1.7 PPE (1000W HID / 25 sq ft)... e.g., 40 Watts / sq ft ~ 68 PPF / sq ft (680 PPF / m2)

3. Nominal Efficiency of current LED Strips is ~ 2.5 PPE. The LED Driver "Sizing" factor or multiplier used is 1.25 (125%) of the LED's Watts for "Reserve Capacity".

4. The -AB suffix XLG and HLG series Meanwell Drivers can be "Current Limited" down to 50% (-A) and then Dimmed between "0 or 10 - 100%" (-B), e.g., HLG-480H-AB can be current adjusted down to 240 Watts (-A, 50%) and then also Dimmed 0 - 240 Watts (-B, 0 - 100%) with a connected 100K Ohm Pot. The -B suffix Drivers are a more versatile alternative than the -A suffix Drivers, can be dimmed down to 0 or 10% (0 Watts for the HLG-480H-48B) with the added 100K Ohm Pot and (IMO) should be the only other alternative to the -AB suffix drivers if dimming is required.

5. Samsung and Bridgelux LED Strips run below 50% max current require minimal to no heatsinkining...
Samsung LT-F564B... viewtopic.php?f=32&t=5872
Bridgelux Vesta 2750G... viewtopic.php?f=32&t=5761

[FREESCRAVEN]

Thank you very much PeteR!

Yes, I had thought of the eb gen2 or eb gen3 too...wired in parallel in this case, right?

Something simpler and less expensive with cobs? Like 1 or 2 cobs.

[PeteR_1]

Thank you very much PeteR!

Yes, I had thought of the eb gen2 or eb gen3 too...wired in parallel in this case, right?

Something simpler and less expensive with cobs? Like 1 or 2 cobs.

Yes, wired in Parallel.
Not a fan of COBs due to poor coverage (hot spots) and lower efficiency.

[FREESCRAVEN]

Thanks again for the suggestions PeteR!

[FREESCRAVEN]

I always get confused with wire in parallel with this driver
This driver is 2.5 A , so with 10 strips, each strip run at 250 mA?
Checking the grow space now, i saw that actually the space to be illuminated is 40 x 45 cm , maybe I could use less strips.

[PeteR_1]

I always get confused with wire in parallel with this driver
This driver is 2.5 A , so with 10 strips, each strip run at 250 mA?
Checking the grow space now, i saw that actually the space to be illuminated is 40 x 45 cm , maybe I could use less strips.

IMO it’s easier to think in Watts per strip, because the Volts and Amps can vary, the 2.5 Amps is only valid for 24Vdc, e.g., the 60 Watt driver @ 15 Vdc outputs 4 Amps!
Operating in the Constant Current Range 14.5 - 24 Vdc outputs 60 Watts. Also 60 Watts / 19.5 = 3.1 Amps

60 Watts / 10 strips = 6 Watts per strip
6 / 19.5 V = 307 mA each

Yes, you can always “size” for the smaller area.

[FREESCRAVEN]

I always get confused with wire in parallel with this driver
This driver is 2.5 A , so with 10 strips, each strip run at 250 mA?
Checking the grow space now, i saw that actually the space to be illuminated is 40 x 45 cm , maybe I could use less strips.

IMO it’s easier to think in Watts per strip, because the Volts and Amps can vary, the 2.5 Amps is only valid for 24Vdc, e.g., the 60 Watt driver @ 15 Vdc outputs 4 Amps!
Operating in the Constant Current Range 14.5 - 24 Vdc outputs 60 Watts. Also 60 Watts / 19.5 = 3.1 Amps

60 Watts / 10 strips = 6 Watts per strip
6 / 19.5 V = 307 mA each

Yes, you can always “size” for the smaller area.

Thanks for explaining this important step that I didn't understand.
So, if i use less strips:

60w / 8 strips = 7.5w per strip
7.5 / 19.5 V = 384 mA

In this case the constant is always 19.5 V, right? What about the wattage? The typical power W is 6.8 , can i go beyond this value as in this case 7.5w?
And if i use less than 8 strips , the value that I must not exceed is 700 mA, right?

[PeteR_1]

Thanks for explaining this important step that I didn't understand.
So, if i use less strips:

60w / 8 strips = 7.5w per strip
7.5 / 19.5 V = 384 mA

In this case the constant is always 19.5 V, right? What about the wattage? The typical power W is 6.8 , can i go beyond this value as in this case 7.5w?
And if i use less than 8 strips , the value that I must not exceed is 700 mA, right?

Yes, The Forward Volts (Vf) of LED strips determine the actual current / Amps.
Yes the value should never exceed the Maximum Rated Amps of the LED strips, but the strips also require heavy duty heat sinks when they are run “hard” near max Amps, typically 75% (525 mA) of max is an average “max” region with adequate heat sinks.

[FREESCRAVEN]

Thanks for explaining this important step that I didn't understand.
So, if i use less strips:

60w / 8 strips = 7.5w per strip
7.5 / 19.5 V = 384 mA

In this case the constant is always 19.5 V, right? What about the wattage? The typical power W is 6.8 , can i go beyond this value as in this case 7.5w?
And if i use less than 8 strips , the value that I must not exceed is 700 mA, right?

Yes, The Forward Volts (Vf) of LED strips determine the actual current / Amps.
Yes the value should never exceed the Maximum Rated Amps of the LED strips, but the strips also require heavy duty heat sinks when they are run “hard” near max Amps, typically 75% (525 mA) of max is an average “max” region with adequate heat sinks.

Perfect, thanks again!